WebDifferential equation f"(x) = f(x) f"(x) - f(x) = 0 [D 2-1] f(x) = 0. The corresponding auxiliary equation D 2 - 1 = 0. Root of auxiliary equation D 2 = 1. ⇒ D = \(±\) 1. Here, m = 1 and n = - 1. Roots are real and different. So complimentary solution is given by. ⇒ f(x) = c 1 e x + c 2 e-x. Put initial condition f(0) = 2 in the above ... WebExample 2: Verify Rolle’s theorem for the function f(x) = x 2 - 4 x + 3 on the interval [1 , 3], and then find the values of x = c such that f '(c) = 0. Solution: f is a polynomial function, therefore is continuous on the interval [1, 3] and is also differentiable on the interval (1, 3). Now, f(1) = f(3) = 0 and thus function f satisfies all the three conditions of Rolle's theorem.

If f (x) is a polynomial function satisfying f (x)f (y) = f (y) + f (xy ...

WebIf f (x) is a polynomial function satisfying the condition f (x) × f (1x) = f (x) + f (1x) and f (2) = 9 then. Class 11. >> Applied Mathematics. >> Functions. >> Graphs of functions. >> If f … crowley makeup

If f x is a polynomial function satisfying f x f 1/ x = f x + f 1/ x ...

Web30 okt. 2024 · If f(x) is a polynomial function of x, satisfying f(x). f(y) = f(x) + f(y) + f(xy) – 2 such that f(1) = 2 and f(2) = 5, asked Oct 30, 2024 in Sets, relations and functions by SumanMandal ( 54.9k points) Web6 mrt. 2024 · Given f (x) is a polynomial function of x, satisfying f (x) ⋅ f (y) = f (x) + f (y) + f (xy) − 2 and that f (2) = 5. Then f (3) is equal to? A) 10 B) 24 C) 15 D) none. Calculus … Web14 apr. 2024 · If \( f \) is a polynomial function satisfying \( f(x) \cdot f\left(\frac{1}{x}\right)=f(x)+f\left(\frac{1}{x}\right) \) and \( f(2)=-3 \), then draw graph o... crowley magie